p69h0.5  Galilean invariance requires that in this case 
 (circuit at rest v=0, Lucas04_23)  Ep = E and Fp = F, 

  1. Starting point, 11Sep2015
   04_12 E transformation particle to observer frames  

/$			ET(r´,t´) = ET(r - v*t,t)  

/*  04_16Derivative form of Ampere's law  
   Take early form 

/$			1/c*∂[∂(t): Bi(r - v*t,t)]  
			=  v/c*r*sin(θ)*φ´*	[   3*q*v/c*(r*cos(θ) - v*t)/|r - v*t|^5  
									 + 1/r/c*∂[∂(t): Ei(r - v*t,t)] 
									] 
/*	doesn't make sense

  2. try (4-12)&(4-19) rather than (4-12)&(4-16)
   04_19E,B for symmetry point charge @v_const . add Faradays law to [Ampere]  

/$			∮[•d(l´),.over.L: (Ei´(r´,t´) - v/cBi(r´,t´))) 
			= -1/c*∮[dAreap,.over.Ap: (∂[∂(t): Bi(r - v*t,t)]•n)
/*	doesn't make sense, 

  3. try (4-11)&(4-13) rather than (4-12)&(4-16)
   from 04_11 E&B_fields_static_plus_induced 

/$			ET(r,v,t) = E0(r,t) + Ei(r,v,t)   B(r,v,t) = B0(r,t) + Bi(r,v,t) 

/*	given Ep = E
/$			Ei´(r´,v´,t´)	= Ei(r,v,t) - E0(r,t)  
/*	from  04_13 Total B magnetic flux density as induced from E0 + Ei 
/$			B(r´,t´)			= (v/c)[ E0(r´,t´) + Ei(r´,t´)      ] 
/*	re-express in observer frame 
/$			B(r - v*t,t)   = (v/c)[ E0(r - v*t,t) + Ei(r - v*t,t) ] 
/*	close, but (v/c) in wrong place...

  4.**what is the "inverse cross-product (_inv)" function such that 
/$			a=βc -> _inv(β,c) = c  [like a=β*c -> /(a,β)=c ]
   
/*  5. **first look at dot product -> inverse dot product
/$			a=β•c -> •_inv(a,β) = c 
			a=β•c = b1*c1 + b2*c2 + b3*c3  
			c = (β•c) * [n1*c1/(β•c) + n2*c2/(β•c) + n3*c3/(β•c)]
			=   a   * [n1*c1/  a   + n2*c2/  a   + n3*c3/  a  ]

/*  unfortunately, this requires explicit knowledge of c
   Hold this for now (interesting challenge - but MAYBE under-constrained?)

  6. Try dot-multiplying by vector to simplify
/$			B(r - v*t,t)  =         (v/c)[ E0(r - v*t,t) + Ei(r - v*t,t) ]    
			(v/c)B(r - v*t,t)   = (v/c)( (v/c)[ E0(r - v*t,t) + Ei(r - v*t,t) ] )  
	using pattern a(βc) = (aβ)c 
			(v/c)B(r - v*t,t)  = (v/c) (v/c) ( E0(r - v*t,t) + Ei(r - v*t,t) )   

/*   but (v/c)(v/c) = 0 as a vector is collinear with itself!?!
   strange "wrong answer" of very basic nature - what am I doing wrong 
   with vector operations?
   
  Interesting challenge, but taking too much time and Im stuck.
   12Sep2015 08h37 - Ill come back to this later 
 23May2016 try multiplying by vX rather than v


/*++++++++++++++++++++++++++++++++++++++
/*add_eqn  "Possible_Lucas_error_or_omission   
   04_24
   E&B for [Faradays + part/obs frameTrans] - towards Fu_Faradays_Law  
 
/$			Ei(r´,v´,t´) = Ei(r - v*t,t) + 1/c*[vBi(r - v*t,t)] 
/%^%			EIpdv(POIo(t),t) = EIodv(POIo,t) + 1/c*[Vonv(PART)BIodv(POIo,t)] 

/*	!!!WRONG - On hold as I havent been able to "move" (v/c) to the right place..  
     AND I still must show that  Ep = E and Fp = F !!